SOLAR ROOFTOP SYSTEM INSTALLATION IN GUJARAT, SOLAR INSTALLATION COST 1 KW = 23,810 Rs

SOLAR SYSTEM ROOFTOP INSTALLATION COST AND CALCULATION OF HOUSELOAD 

GUJARAT RESIDENTIAL SOLAR RUFFTOP YOJNA 2018-19, I-SMART SCHEME IN GUJARAT, SOLAR PANEL SUBSIDY BY GOVERNMENT IN 2020, SOLAR ROOFTOP SUBSIDY-GEDA

The solar system is one of the most economical electricity generations right now. The solar system is the most convenient electricity generation system. Of course, the Installation cost of the solar system is too high. India leading to install a convenient energy generation system in the future. In the next 5-10 years, most electricity generation from renewable sources will be higher than the energy generation from nonrenewable energy sources. Currently under PM Narendra Modi in Madhya Pradesh (REVA) government installs the largest solar system among continental of Asia. Solar systems have many disadvantages in terms of efficiency and effectiveness. But in future which type of problems will come, the solar system will be the only option for that problem. May be Solar system doesn't work properly in the rainy season, but if we have a hybrid solar system than we have the opportunity to supply power to the consumers or Official electricity board in our region. India has the second-largest populated nation in the world after China, but in the future India will lead in that rank and will become the nation that has the most population with less geometric land area. In the future one of the main problems, we will face that land area. The land cost will become higher per square meter. Also, the government will shut down the Powerplant which depends on nonrenewable energy sources like coal, gas, petroleum, Diesel, and Nuclear. Now the government focus on installing the Powerplant which depends on renewable energy sources like Hydro, Solar, Wind, Tidal, Bio-gas.

            To produce awareness about the solar system the Indian government started many campaigns. The government of India gives a subsidy. Both national government and state governments give the subsidy to the person who installs solar system. Many organizations and companies have a solar system; they know what is best for business. In the Gujarat Solar system installed in many government buildings. Government of India give subsidy on the solar system with different ration like, For installing 1KW solar system the government of India gives us Subsidy around Rs 14490/- when total installation cost will be around Rs 48300/-. Like the Central government of Gujarat also give subsidy. The government of Gujarat gives subsidy on installing a 1KW solar system around Rs. 10000/- under "Gujarat Residential Solar Rufftop Yojna 2018-19. So the total installation cost of the 1KW solar system would be around Rs. 23810/- .The total land area required for installation 1 KW solar system would be 100 sq.ft. Both Central and state governments provide subsidy on different terms regarding KW. The subsidy amount may increase if our solar system installation capacity should be high. The central government provides more and more amount if we increase our total installed capacity. Like subsidy amount will increase concerning the KW (Install capacity of the solar system). But the terms and conditions of the government of Gujarat are different. The Government of Gujarat provides Rs. 10000/- on installing 1 KW solar system, and Rs. 20000/- on installing 2KW solar system but over 2KW subsidy provide by state governments would be the same, there is no difference in subsidy amount in between 5KW and 15KW.

SOLAR ROOFTOP YOJNA COST IN GUJARAT

Install Capacity	1 KW	2 KW	4 KW	6 KW	8 KW
State Government subsidy	10.000	20,000	20,000	20,000	20,000
Central Government Subsidy	14,490	28.980	57.960	86, 940	1,15.200
Total Install Cost	48,300	96,600	1,93,200	2,89,800	3,84,000
Final Installation cost after Subsidy	23,810	47,620	1,52,240	1,82,860	2,48,800

SPECIFICATION OF 1 KW HYBRID SOLAR SYSTEM ON ROOFTOP (ELECTRICITY GENERATION AND SUPPLY TO THE CONSUMER

Specification	Description
Installed Capacity of Solar system	1 KW
Solar Panel Quantity	3
Off Grid Solar Inverter	1 KW
AC Cable	20 m
DC Cable	30 m
Junction Box	1 .
Space Required	100 sq. feet
Watt Per Solar Panel	335 Watt
Total Solar Structure	1 KW
Battery	2
All Accessories Required for Installation	Fasteners, Lightning Arrestor, Earthling System, Cable Tie, Crimping Tool
Total Price	23,810 (Primary Cost)

 

CALCULATION OF SPECIFIC ONE HOUSE LOAD FOR INSTALLING SOLAR SYSTEM

• CACULATION OF SOLAR PV SYSTEM FOR OWN HOME:- (GENERAL)
• CACULATION OF SOLAR PV SYSTEM FOR OWN HOME:- (ENERGT EFFICIENT)
• COMPARASION OF SIZE OF PV EQUIPMENT AFTER & BEFORE USE OF ENERGY EFFICIENT APPLIANCES
• PAYBACK CALCULATION
• TYPES OF PV CELL
• TYPES OF PV BATTERY

CACULATION OF SOLAR PV SYSTEM FOR OWN HOME:

APPLIANCES	WATT RATIING	UTILIZATION HOURS (PERDAY)	NO. OF APPLIANCES	Wh/DAY
Fluorescent lamp	18 watt	04 hours	4	288
Tubelight (T-12)	40watt	06 hours	3	750
Ceiling Fan	75 watt	09 hours	2	1350
Refrigerator(185L)	250 watt	08 hours	1	2000
Iron	1100 watt	01 hours	1	1100
Laptop	50 watt	02 hours	1	100
TV CRT	120 watt	09 hours	1	1080
Mixer grinder	750 watt	0.5 hours	1	375

Total consumed 7013 wh/day

Total Wh/day to be provided by PV panels (Considering 30% losses in the system)                                   

‘‘Total Wh/day to be provided by PV = 7013 ×1.3 = 9117 Wh per day’’

·       Determine watt-peak:-

Divide the total watt-hours per day needed from the PV modules by 3.43 to get the total Watt-peak rating needed for the PV panels needed to operate the appliance.

watt-peak = 9117/3.43  =  2658 watt peak (Wp)

“watt peak (Wp) = 2658”

·         Determine PV modules:-

Divide the answer obtained in watt-peak by the rated watt-peak of the PV modules available to you = 2658 /110 = 24 modules

‘‘So the system should be powered by at least 110 Wp, 24 modules’’

·         Determine Inverter size:-

Total watt of appliances = 2403watt.

For safety inverter should be chosen 25-30% bigger size.

“So Inverter size should be above 3123 watt or greater.” 

·         Determine Battery size:-

(Total watt-hours of Appliance=9117) × (Days of autonomy=1)

     battery capacity=

(Battery losses=85%) × (Depth of Discharge=60%) × (Rated battery voltage=12)

~~ 1489 Amp-hours

“So battery should be rated for 12 volt, 1490AH for 01 day autonomy.”

·         Solar Charge controller sizing:-

PV module specification

Pm = 110 Wp (Watt-peak)

Vm = 16.7Vdc

Im = 6.6 Amp

Isc = 7.5 Amp

Solar charge controller rating = (24 strings×7.5amp) × 1.3 ~ 234 Amp

‘‘So the solar charge controller should be rated at 234 amp and 12 volt or greater.”

CACULATION OF SOLAR PV SYSTEM FOR OWN HOME: (ENERGY EFFICIENT)

APPLIANCES	WATT RATIING	UTILIZATION HOURS (PER DAY)	NO. OF APPLIANCES	Wh/DAY
Fluorescent lamp (OLD)	18 watt	04 hours	4	288
LED lamp (NEW)	13 watt	04 hours	4	208
Tubelight (T-12)	40 watt	06 hours	3	750
Tubelight (T-5) (NEW)	28 watt	06 hours	3	504
Ceiling Fan (OLD/NEW)	75 watt	09 hours	2	1350
Refrigerator(185L)	250 watt	08 hours	1	2000
Iron (OLD/NEW)	1100 watt	01 hours	1	1100
Laptop (OLD/NEW)	50watt	02 hours	1	100
TV CRT	120 watt	09 hours	1	1080
TV LED (NEW)	95 watt	9 hours	1	495
Mixer grinder (OLD/NEW)	750 watt	0.5 hours	1	375

 Total consumed 6132 Wh/day

Total Wh/day to be provided by PV panels (Considering 30% losses in the system)                                   

‘‘Total Wh/day to be provided by PV = 6132×1.3 = 7972 Wh per day’’

·         Determine watt-peak

Divide the total watt-hours per day needed from the PV modules by 3.43 to get the total Watt-peak rating needed for the PV panels needed to operate the appliance.

watt-peak = 9493/3.43  =  2324.1 watt peak (Wp)

“watt peak (Wp) = 2324.1”

·         Determine PV modules

Divide the answer obtained in watt-peak by the rated watt-peak of the PV modules available to you. = 2324.1/110 =  21.12modules ~ 22 modules

‘‘So the system should be powered by at least 110 Wp, 22 modules’’

·         Determine Inverter size

Total watt of appliances = 2321 watt.

For safety inverter should be chosen 25-30% bigger size.

“So Inverter size should be above 3017 watt or greater.”

·         Determine Battery size

(Total watt-hours of Appliance=7972) × (Days of autonomy=1)

     battery capacity=

(Battery losses=85%) × (Depth of Discharge=60%) × (Rated battery voltage=12)

~~ 1302 Amp-hours

“So battery should be rated for 12 volt, 1302 AH for 01 day autonomy.”

·         Solar Charge controller sizing

PV module specification

Pm = 110 Wp (Watt-peak)

Vm = 16.7Vdc

Im = 6.6 Amp

Isc = 7.5 Amp

Solar charge controller rating = (22 strings×7.5amp) × 1.3= 215 Amp

‘‘So the solar charge controller should be rated at 215 amp and 12 volt or greater.”

COMPARASION OF SIZE OF PV EQUIPMENT AFTER & BEFORE USE OF ENERGY EFFICIENT APPLIANCES

	GENERAL LOAD	ENERGY EFFICIENT LOAD
TOTAL WH/DAY	9117	7972
WATT-PEAK (WP)	2658	2324
PV MODULE	24	22
INVERTER SIZE (WATT)	3123	3017
BATTERY SIZE (AH)	1490	1302
CHARGE CONTROLLER RATING (AMP)	234	215

PAYBACK CALCULATION

TYPE OF LOAD	LAMP	TUBELIGHT	TV
LOAD WATTAGE (OLD)	18*4 Fluorescent lamp	40*3 Tubelight (T-12)	120 TV CRT
LOAD WATTAGE (NEW)	13*4 LED lamp	28*3 Tubelight(T-5)	55 TV LED
TOTAL INVESTMENT	350	400	17000
EARNING FROM OLD APPLIANCE	NA	NA	2500
MONTHLY PROFIT (KWH)	2.6	6.4	17.55
MONTHLY SAVING IN (RUPEE)	20.8	51.2	140.4
PAYBACK PERIOD	17 MONTH	8 MONTH	81 MONTH

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